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Home/ Questions/Q 8740339
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T11:06:47+00:00 2026-06-13T11:06:47+00:00

I made this code to select one checkbox when I click on a image

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I made this code to select one checkbox when I click on a image but this don’t work.

$linkToInterview = 'checkById(document.myform.checkbox,$interview_id)';
?>
<a href="javascript:void(0);" onclick='<?=$linkToInterview?>'><img src="<?=siteConfig::img_dir?>new_photos/video.gif" style="border:0px"/></a>

And Javascript function:

<script type="text/javascript">
function checkByID(chk,id) {
chk[id].checked = true ;
}
</script>

And checkbox code:

<td><input type="checkbox" name="checkbox" value="<?php echo $fet['id']; ?>"
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T11:06:48+00:00Added an answer on June 13, 2026 at 11:06 am
    $linkToInterview = 'checkById(document.myform.checkbox,$interview_id)';
    

    will contain literal $interview_id, which means you’re outputting

    <a href="..." onclick='checkById(document.myform.checkbox,$interview_id)'>
    

    To contain the content of $interview_id, you should use double quote, add a single quote around it, and use double quote on HTML output:

    <?php
    $linkToInterview = "checkById(document.myform.checkbox,'$interview_id')";
    ?>
    <a href="..." onclick="<?=$linkToInterview?>;">
    

    This will output (assuming your $interview_id="test"):

    <a href="..." onclick="checkById(document.myform.checkbox,'test');">
    
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