Question

I make code to display multiple pages (max. 5 lines/page) with persons from one list:

/* PRE:     page : number of the page we want to show, starting with 1
 * RETURNS: pagenumber of the page showing if there is one, 0 otherwise  */


const int buf_length = 255;
const int max_num_lines = 15;
const int num_person_per_page = max_num_lines / 3;
const int num_person = person_get_num_person(personmgr);
char buf[buf_length+1];
int i, count, cur = 0;

/* List Header */ 
snprintf(buf, buf_length, "List of person on page (%d/%d)):", page, num_person/num_person_per_page);
list_set_text( list, cur++, buf);
list_set_hilight(list, -1); 

If list have number of persons witch isn’t multiples of 5 (72 – in my example), list header of last page returns total number of page as 14 instead of 15 (14/15).

First page list header:

List of person on page: 1/14:
01. AAA
02. BBB
03. CCC
04. DDD
05. EEE

Second page list header:

List of person on page: 2/14:
06. FFF
07. GGG
08. HHH
........................

Last page list header:

List of person on page: 14/15:
71. XXX
72. ZZZ     

I want a to round up to next integer number (pages number to be displayed correctly).

72 / 5 = 14.4 => 15
70 / 5 = 14   => 14
36 / 5 = 7.2  => 8

First page list header:

List of person on page: 1/15:
01. AAA
02. BBB
03. CCC
04. DDD
05. EEE

Second page list header:

List of person on page: 2/15:
06. FFF
07. GGG
08. HHH
........................

Last page list header:

List of person on page: 15/15:
71. XXX
72. ZZZ

Answer 1

You can write (n + 4) / 5 to integrally compute the mathematical ceiling of n / 5: If n is already a multiple of 5 then you’re adding 4 / 5 == 0, and otherwise you’re adding 1.