Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8676589
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T20:14:04+00:00 2026-06-12T20:14:04+00:00

I make the application which need internet access. And I want that it will

  • 0

I make the application which need internet access. And I want that it will showing AlertDialog with two buttons (“Retry” and “Quit”). So, I try this:

void prepareConnection() {
    if(!checkInternetConnection()) {
        AlertDialog.Builder alert = new AlertDialog.Builder(this);
        alert.setMessage(R.string.internet_not_available);
        alert.setTitle(R.string.app_name);
        alert.setPositiveButton(R.string.retry, new OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                prepareConnection();
            }});
        alert.setNegativeButton(R.string.quit, new OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                finish();
            }});
        alert.show();
    }
}

boolean checkInternetConnection() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    if ((cm.getActiveNetworkInfo() != null) && cm.getActiveNetworkInfo().isAvailable() && cm.getActiveNetworkInfo().isConnected()) {
        return true;
    }
    return false;
}

But AlertDialog with OnClickListener working asynchronously and prepareConnection() doesn’t wait before Internet will be connected and user click “Retry”. I think my problem in a code structure. How to make it right?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-12T20:14:05+00:00Added an answer on June 12, 2026 at 8:14 pm

    I used something like this

    boolean connection = checkNetworkConnection();
        if(!connection){
            createAlertDialog();
        }
        else{
            whenConnectionActive();
        }   
    

    and createAlertDialog() function

    public void createAlertDialog(){    
        final Dialog dialog = new Dialog(this);
        dialog.setContentView(R.layout.custom_dialog);
        dialog.setTitle("Message");
        Button continueButton = (Button) dialog.findViewById(R.id.dialogContinueButton);
        TextView tw = (TextView) dialog.findViewById(R.id.dialogText);
        Button finishButton = (Button) dialog.findViewById(R.id.dialogFinishButton);
    
        tw.setText("Message");
        continueButton.setOnClickListener(new OnClickListener(){
            public void onClick(View v) {
                dialog.dismiss();
                boolean connection = checkNetworkConnection();
                if(!connection){
                    dialog.show();
                }
                else{
                   prepareConnection();
                }
            }   
        });
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I need to write application in .NET which will be make some calculations on
I just want to know that can i make an application which have some
I need to make an application which has two windows: Window 1 Contains 6
I have a relatively simple application which I need to make native Mac OSX
I am trying to make a small application which has the capability of showing
I am trying to make a simple application which will send the user to
Suppose I want to make a Web application which uses a fixed width and
I want to make a Windows Form Application which only shows a timer as:
I need to make an application which dynamically generates some number of forms and
I need to make an application in which i need to send smses through

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.