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Home/ Questions/Q 6787227
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T17:20:27+00:00 2026-05-26T17:20:27+00:00

I may be wrong on what I think .splice() is meant to do, but

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I may be wrong on what I think .splice() is meant to do, but I thought it removed one element of an array. All I want to do here is remove “pears”, but it doesn’t work:

var my_array = ["apples","pears","bananas","oranges"];

my_array.splice($.inArray("pears",my_array));

$.each(my_array, function(k,v) {
    document.write(v+"<br>");
});

Also at http://jsfiddle.net/jdb1991/nV95v/

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  1. Editorial Team
    Editorial Team
    2026-05-26T17:20:27+00:00Added an answer on May 26, 2026 at 5:20 pm

    You’re missing two arguments:

    • $.inArray wants the second argument to be the subject array
    • splice accepts a second argument to specify the number of elements to be deleted

    The code becomes:

    var my_array = ["apples","pears","bananas","oranges"];
    
    my_array.splice($.inArray("pears", my_array), 1);
    
    $.each(my_array, function(k,v) {
        document.write(v+"<br>");
    });
    

    Live example

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