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Home/ Questions/Q 8914555
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T04:45:06+00:00 2026-06-15T04:45:06+00:00

I might be misunderstanding type casting, but here is my problem. I’ve got an

  • 0

I might be misunderstanding type casting, but here is my problem.

I’ve got an Android View with a ToggleButton:

<LinearLayout
    ... >
    <ToggleButton
        android:id="@+id/btnRec"
        android:layout_width="125dp"
        android:layout_height="wrap_content"
        android:textOff="Start TEST"
        android:textOn="Stop TEST" />
    ...
</LinearLayout>

Then in my activity I declare a ToggleButton variable:

private ToggleButton mRecordButton = null;

Now, I implement a subclass of ToggleButton, called RecordButton:

class RecordButton extends ToggleButton {

    OnCheckedChangeListener clicker = new OnCheckedChangeListener() {
        ...
    };

    public RecordButton(Context ctx) {
        super(ctx);
        setOnCheckedChangeListener(clicker);
    }
}

And finally in onCreate I find the button by its id:

mRecordButton = (RecordButton) findViewById(R.id.btnRec);

This throws a ClassCastException.

Why? How can I cast it to RecordButton (the subclass) from ToggleButton (the superclass)?

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  1. Editorial Team
    Editorial Team
    2026-06-15T04:45:07+00:00Added an answer on June 15, 2026 at 4:45 am

    in your XML, replace the regular ToogleButton with the custom one..

    <LinearLayout
    ... >
    <package.class.RecordButton
        android:id="@+id/btnRec"
        android:layout_width="125dp"
        android:layout_height="wrap_content"
        android:textOff="Start TEST"
        android:textOn="Stop TEST" />
    ...
    

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