Question

I must be going crazy but why is Groovy findIndexValues returning List<long>? Can I get the indices in Integer?

foo = ['a','b','d','e', 'e','e']
indices  = foo.findIndexValues { it == 'e'}
indices.each { println foo[it] }

The above will crash because foo collection cannot handle a long as a accessing index. Am I not using the language as it should be?

Answer 1

That’s how that method works. It traverses the collection with an iterator and keeps track of the matching indexes as longs. In theory, it supports collections larger than Integer.MAX_VALUE, although I’m doubtful this is useful in practice.

You can work around it with:

indices.each { println foo[it as int] }