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Home/ Questions/Q 6944777
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:21:04+00:00 2026-05-27T13:21:04+00:00

I need 100 small divs for my chart, every time I generate them, I

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I need 100 small divs for my chart, every time I generate them, I they all appear as the same height; the last value from the array.

var valuesG = new Array(100);
for (i = 0; i < valuesG.length; i++ ) {
    valuesG[i] = Math.floor(Math.random() * 101);   
    $("#second").append("<div class='single'></div>");
    $(".single").css('height', valuesG[i])
}

Any ideas why this is happening?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:21:04+00:00Added an answer on May 27, 2026 at 1:21 pm

    You are applying the new height to ALL the .single elements in every iteration. In the last iteration, they end up having the same height.

    You could do it like this:

    $('<div class="single">')
        .css('height', valuesG[i])
        .appendTo($('#second'));
    

    Also, your code is not very efficient, take a look at this:

        var valuesG = [], //array literal
            $elements = $(); //empty jQuery object
    
        for (var i = 0; i < 100; i++) { //we don't have to query array length each iteration
            valuesG[i] = Math.floor(Math.random()*101); 
    
            //collect the elements into a jQuery object
            $elements = $elements.add($('<div class="single">').css('height', valuesG[i]));
        }
    
        $elements.appendTo($("#second")); //insert to DOM once - much quicker
    

    jsFiddle Demo

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