Question

I need a function:

function isSame(a, b){
} 

In which, if a and b are the same, it returns true.
, I tried return a === b, but I found that [] === [] will return false.
Some results that I expect this function can gave:

isSame(3.14, 3.14);  // true  
isSame("hello", "hello"); // true  
isSame([], []); // true  
isSame([1, 2], [1, 2]); // true  
isSame({ a : 1, b : 2}, {a : 1, b : 2}); //true  
isSame([1, {a:1}], [1, {a:1}]);  //true

Answer 1

There are some examples, adapted from scheme, on Crockford’s site. Specifically, check out:

function isEqual(s1, s2) {
    return isAtom(s1) && isAtom(s2) ? isEqan(s1, s2) :
            isAtom(s1) || isAtom(s2) ? false :
            isEqlist(s1, s2);
}

It can all be found here:

http://javascript.crockford.com/little.js

Here is a working example:

http://jsfiddle.net/FhGpd/

Update:

Just wrote some test cases based on the OP. Turns out I needed to modify the sub1 function to check <= 0 not === 0 otherwise isEqual(3.14, 3.14) blew the stack. Also, isEqual does not work for object comparison, so you are on your own there. However, if you follow the examples on Crockford’s site you will see how easy and fun it is to write recursive methods that could be used to check for object equality.