Question

I need a function with the following signature:

public void requiredFunction(int[][] array, int row, int column) {
    // code
}

The function should increment all the values in the same row, column and diagonal as array[row][column] (except array[row][column] itself).

Suppose I have the following 2D array:

int[][] array = {
    0 0 0 0 0 0
    0 0 0 0 0 0
    0 0 0 0 0 0
    0 0 0 0 0 0
    0 0 0 0 0 0
    0 0 0 0 0 0
};

Now when I call this function with the following values:

requiredFunction(array, 2, 2);

It should convert the array to:

array = {
    1 0 1 0 1 0
    0 1 1 1 0 0
    1 1 0 1 1 1
    0 1 1 1 0 0
    1 0 1 0 1 0
    0 0 1 0 0 1
};

If you think of the array as a chess board, then the function takes the position of the queen (row and column) and increments those places on the chess board, that the queen can move to.

Answer 1

Here is something shorter :

public void requiredFunction(int[][] array, int row, int column) {
  for (int i = 0; i < array.length; ++i) {
      for (int j = 0; j < array[i].length; ++j) {
           if (i == column && j == row)
               continue;
           if (Math.abs(i - column) == Math.abs(j - row) ||
               i - column == 0 || j - row == 0)
               array[i][j]++;                                    
      }
  }
}