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Home/ Questions/Q 251667
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:36:49+00:00 2026-05-11T21:36:49+00:00

I need a multidimensional array of chars that is dynamic in only one dimension…

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I need a multidimensional array of chars that is dynamic in only one dimension…
I have to store a pair of strings with a length of 10 (or less) chars each, but with a variable number of “pairs”.

My idea was this

char (*instrucao)[2][10];

Which gives me a pointer to a 2×10 array of chars, but this is not working properly when i do something like this:

char strInstrucoes[117], *conjunto = calloc(21, sizeof(char));
instrucao = calloc(1, sizeof(char[2][10]));
conjunto = strtok(strInstrucoes,"() ");
for(i = 0; conjunto != NULL; i++){
    realloc(instrucao, i+1*sizeof(char[2][10]));
    sscanf(conjunto,"%[^,],%s", instrucao[i][0], instrucao[i][1]);
    printf("%s | %s\n", instrucao[i][0], instrucao[i][1]);
    conjunto = strtok(NULL, "() ");
}

Having strInstrucoes as (abc,123) (def,456) (ghi,789), I don’t matrix with 3 lines of 2 pairs each like this:

abc | 123
def | 456
ghi | 789

but instead this is what I’m getting:

abc | 123
def | 45def | 45de
ghi | 789

What’s the right way to do this?
Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:36:50+00:00Added an answer on May 11, 2026 at 9:36 pm

    You should assign the pointer the new address realloc returns

    instrucao = realloc(instrucao, (i+1)*sizeof(char[2][10]));
    

    Note that for error checking, you may desire to assign to a new pointer and check for NULL. Also note the parens – you basically just added i instead of multiplying with the required size. Easily overseen.

    Note that there is no need for the initial calloc. Just initialize instrucao to NULL, and realloc will behave like malloc when first passed a null pointer.

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