Question

I need a PHP function that displays the previous year until August 1, at which point it should display the current year.

For example:

• today is May 12, 2011, so this should echo “2010”
• when it’s August 1, 2011 this should echo “2011”
• …continue to echo “2011” until August 1, 2012
• on August 1, 2012, it should echo “2012”
• etc.

Please let me know if you have any questions. Thanks in advance!

Answer 1

Here ya go:

$year = date('Y') - 1;
$month = date('n');

if($month >= 8) $year++;

echo $year;

Demo: http://codepad.org/qOx1TO95