Question

I need a query that compares a list of strings from one table with a list of strings in another table.

The pseudo code might be:

for each word in slang
 if not word.contains(animalName) {
  print animalName
 }
next slang

It doesn’t have to be fast, it’s not for production. I’m trying to debug something, and the result of the query is what I need to work with.

Thank you.

Answer 1

All slang words that do not contain an animal name:

SELECT word 
FROM slang 
WHERE NOT EXISTS (
  SELECT * 
  FROM animals 
  WHERE word LIKE '%'+ animalName + '%')