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Home/ Questions/Q 6533733
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:09:50+00:00 2026-05-25T10:09:50+00:00

I need a Query that without any changes work on these three different database

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I need a Query that without any changes work on these three different database server : MySQL, MSSQL, PostgreSQL .
In this query i have to to calculate a column with the following expression that work correctly on MySQL :

COUNT(DISTINCT field_char,field_int,field_date) AS costumernum

The fields in the distinct are of different type :

field_char = character
field_int  = integer
field_date = datetime

The expression is inside a parent query select, so if i try to achieve the result with a sub query approach, i stumble in this situation :

SELECT t0.description,t0.depnum
(select count(*) from (
  select distinct f1, f2, f3 from salestable t1
  where t1.depnum = t0.depnum
) a) AS numitems
FROM salestable t0

I get an error with this query, how can i get the value of the parent query ?

The expression work correctly on MySQL but i get an error when i try to execute it on Sql Server or PostgreSQL (the problem is that the count function doesn’t accept 3 arguments of different type on MSSQL/PostgreSQL), is there a way to achieve the same result with an expression that work in each of these database server (SQL Server, MySQL, PostgreSQL ) ?

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  1. Editorial Team
    Editorial Team
    2026-05-25T10:09:51+00:00Added an answer on May 25, 2026 at 10:09 am

    A general way to do this on any platform is as follows:

    select count(*) from (
      select distinct f1, f2, f3 from table
    ) a
    

    Edit for new info:

    What if you try joining to the distinct list (including the dept) and then doing the count? I created some test data and this seems to work. Make sure the COUNT is on one of the t1 columns – otherwise it will mistakenly return 1 instead of 0 when there are no corresponding entries in t1.

    SELECT t0.description, t0.depnum, count(t1.depnum) as 'numitems'
    FROM salestable t0
    LEFT JOIN (select distinct f1,f2,f3,depnum from salestable) t1
      ON t0.depnum = t1.depnum
    GROUP BY
      t0.description, t0.depnum
    
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