Question

I need a random function for number betwen 11 and 99. I wrote this:

int random (void){
    int i2;
    i2=11+(rand()%99);      
    return i2;
}

but the numbers go over 99. Why?

Answer 1

Because if rand() return 98, then 98 % 99 is 98 and 98 + 11 > 99.

To do this, you need

i2 = 11 + ( rand() % 89 );

rand() % 89 will give you numbers [0, 88], so +11 would become [11, 99].

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By the way, don’t forget to srand( time( NULL ) ), otherwise it will (most probably) generate the same sequence of (pseudo) random numbers all the time.