Question

i need a reg exp (to do a preg_replace) to find all <font> tags with a style="..." attribute…

the problem is that i need to match ONLY the <font> with a style attribute AND a value of

"height: 0;overflow: hidden;width: 0; position: absolute;"...

another problem, the style attribute may be in different positions;

ex.

<font  color="white"  style="height: 0;overflow: hidden;width: 0; position: absolute; font-family:courier; font-size:10px" >

or

<font  style="height: 0;overflow: hidden;width: 0; position: absolute; font-family:tahoma; font-size:14px" color="red"   >

EDIT: solved it with:

#</?font [^>]*\bheight: 0;overflow: hidden;width: 0; position: absolute;[^>]* >(.+</font[^>]*>|)#is

(find the tag with that style and everything it contains)

that reg exp in a preg_replace() seems to work !!

Answer 1

If you are sure that your HTML is nice enough to be accesible by Regex (i.e. no comments, nothing malformed, the style css does not contain comments, … ) and want to only match the opening tag (nesting is a no-no with regex), you can try

<font [^>]*\bstyle="([^"]*)"[^>]*>

This regex matches every font-tag with a style attribute, and contains the value of this attribute in its only capturing group.

Edit: Maybe I misunderstood the question. If you need the style attribute to be the value you specified, use

<font [^>]*\bstyle="height: 0;overflow: hidden;width: 0; position: absolute;"[^>]*>