Question

I need a regular expression for “\/” (It is not a V, it is a backslash and a forwardslash(?))
It is okay to only catch the “\” and replace it with a “” nothing.

Tried:

parsed= parsed.replace(Matcher.quoteReplacement("\\/"), "");
parsed= parsed.replace("\\", "");
parsed= parsed.replace("\\\", "");
parsed= parsed.replace("\\\\", "");

None of them works.
Im little confused.

Any help will be appreciated.

Answer 1

Almost there. To remove \/, use this :

parsed= parsed.replaceAll("\\\\/", "");

\\ is a \ in a java string, and you need to have \\ to have your escaped \ in a regex. Hence the \\\\.

EDIT :

I may have misunderstood. To remove all / ,simply use

 parsed= parsed.replaceAll("/", "");

No need to escape, then, but it’s better to use the correct method.