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Home/ Questions/Q 6639023
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:30:20+00:00 2026-05-25T23:30:20+00:00

I need a regular expression to match against all punctuation marks, such as the

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I need a regular expression to match against all punctuation marks, such as the standard [,!@#$%^&*()], but including international marks like the upside-down Spanish question mark, Chinese periods, etc. My google-fu is coming up short. Does anyone have such a regular expression on hand that’s compatible with Javascript?

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:30:21+00:00Added an answer on May 25, 2026 at 11:30 pm

    If it’s possible for you to use a plugin, there is a plugin for JavaScript: XRegExp Unicode plugins. That adds support for Unicode categories, scripts, and blocks (I personally have only read about it, I never used it).

    With this plugin it should be possible to use Unicode categories like \p{P} as explained at regular-expressions.info.

    Update:
    OK, I tested it, and it seems to work fine.

    You need to get the lib from XRegExp and additionally the Unicode Base and Unicode Category plugins (linked above).

    <script src="xregexp.js"></script>
    <script src="addons/unicode-base.js"></script>
    <script src="addons/unicode-categories.js"></script>
    <script>
        var unicodePunctuation = XRegExp("^\\p{P}+$");
    
        alert(unicodePunctuation.test("?.,;!¡¿。、·")); // true
    </script>
    

    The above alerts true. I included some Spanish and Chinese punctuation in my test string, "?.,;!¡¿。、·".

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