Home/ Questions/Q 6320519
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-24T15:59:14+00:00

I need a single line bash command that takes a piped input and returns

  • 0

I need a single line bash command that takes a piped input and returns true or false depending if it match a string or not..

This seems to work for the true or false part:

test `expr match "Release:11.04" "Release:11.04"` = 13 && echo true || echo false

But I cannot get it to work properly with the other command’s output..

What I need would be something like this:

test `expr match "`lsb_release -r`" "Release:11.04"` = 13 && echo true || echo false

So I tried with xargs, but I can’t get it to work:

lsb_release -r | xargs -I {} test `expr {} "Release: 11.04"` = 13 && echo True || echo False

Also, if any of you happens to know a shorter way to achieve this, it would be greatly welcome.

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    You could use the $(cmd) syntax.

    test $(expr match "$(lsb_release -r)" "Release:11.04") = 13 && echo true || echo false

    Though on my system there is a tab in the output of lsb_release after ‘:’, so you may want to doublecheck your checks.

    And actually after fiddling a bit, I think this would be a nicer way with bash (tested on Debian system):

    [[ "$(lsb_release -r)" =~ $'Release:\t6.0.2' ]] && echo true || echo false
    • 0