Question

I need a SQL query that returns the top 2 Plans by PlanDate per ClientID. This is all on one table where PlanID is the PrimaryID, ClientID is a foreignID.

This is what I have so far –>

SELECT *
FROM [dbo].[tblPlan] 
WHERE [PlanID] IN (SELECT TOP (2) PlanID FROM [dbo].[tblPlan] ORDER BY [PlanDate] DESC)

This, obviously, only returns 2 records where I actually need up to 2 records per ClientID.

Answer 1

This can be done using ROW_NUMBER:

SELECT PlanId, ClientId, PlanDate FROM (
    SELECT ROW_NUMBER() OVER (PARTITION BY ClientId ORDER BY PlanDate DESC) rn, *
    FROM [dbo].[tblPlan]
) AS T1
WHERE rn <=2

Add any other columns you need to the select to get those too.