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Home/ Questions/Q 6331511
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:05:00+00:00 2026-05-24T18:05:00+00:00

I need a way to know the uniqueness per user, whether it be for

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I need a way to know the uniqueness per user, whether it be for iPhone, Android, or Windows Phone devices. If there is no universal way, i was wondering if saving the phone number would be legitimate (i.e. legal).

Anybody have any experience in this?

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  1. Editorial Team
    Editorial Team
    2026-05-24T18:05:00+00:00Added an answer on May 24, 2026 at 6:05 pm

    I don’t believe there is, or even could be, a cross platform way to do this. Each device has it’s own SDK platform and API’s.

    UPDATE: Slight correction on my previous statement as it looks like PhoneGap may be able to give you a cross platform approach.

    PhoneGap:

    var deviceID = device.uuid;
    

    See: http://docs.phonegap.com/phonegap_device_device.md.html

    Here’s how you could do it on each platform:

    Android:

    android.telephony.getDeviceId()
    

    See: http://developer.android.com/reference/android/telephony/TelephonyManager.html#getDeviceId%28%29

    iPhone:

    [[UIDevice currentDevice] uniqueIdentifier]
    

    See: http://developer.apple.com/library/ios/#documentation/uikit/reference/UIDevice_Class/Reference/UIDevice.html

    Windows Phone 7:

    DeviceExtendedProperties.GetValue("DeviceUniqueId")
    

    See: http://msdn.microsoft.com/en-us/library/ff941122%28v=VS.92%29.aspx

    Blackberry:

    FindDeviceForUserResult result=coreWebService.findDeviceForUser(userId, locale, true);
    if (result.getFindDeviceForUserReturnStatus().getCode()!= FindDeviceForUserReturnStatusEnumType.SUCCESS)
    { 
           // handle any errors
    }
    if (result.getDevice() == null)
    { 
           // notify the user
    }
    int deviceID = result.getDevice().getDeviceId();
    

    See: http://docs.blackberry.com/en/developers/deliverables/7283/Find_BlackBerry_devices_628863_11.jsp

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