I need an action to create MyModel type with some fields and also some

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Asked: June 3, 20262026-06-03T23:49:57+00:00 2026-06-03T23:49:57+00:00

I need an action to create MyModel type with some fields and also some

0

I need an action to create MyModel type with some fields and also some files to upload to DB. So this is a part of my View:

@using(Html.BeginForm()) {

<fieldset>
 <dl>
    <dt>
  @Html.LabelFor(model => model.Name)
</dt>
<dd>
  @Html.EditorFor(model => model.Name)
  @Html.ValidationMessageFor(model => model.Name)
</dd>
    <dt>
 @Html.LabelFor(model => model.NeededFiles)
</dt>
    <dd>
@foreach(var item in Model.NeededFiles) { 
 <div style="margin:5px;">
       @Html.Label(item.Title)
       <input type="file" name="@item.Name" />
 </div>
}
     </dl>
 </fieldset>
 <input type="submit" value="Create" class="button red" />
}

But in post Action I have some problem to get file Path:
This is my Action:

[HttpPost]
public ActionResult Create(MyModel ViewModel FormCollection collection, IEnumerable<HttpPostedFileBase> files) {

 //....
 }

Request.Files is null so I can’t use it and I don’t know why. also files IEnumerable<HttpPostedFileBase> is null. then I try to get from FormCollection
so I use this:

   string filePath = collection.GetValue(item.Name).AttemptedValue;

but filePath just returned file Name not File path, I don’t understand. when I choose file I can see all path in input but when I want to get it just file Name returned. where is my problem? what is your suggestion?