Question

I need an empty char array, but when i try do thing like this:

char *c; 
c = new char [m];
int i;
    for (i = 0; i < m; i++)
    c[i] = 65 + i;

and then I print c. can see that c = 0x00384900 "НННННННээээ««««««««юоюою"
after cycle it becomes: 0x00384900 "ABCDEFGээээ««««««««юоюою"
How can I solve this problem? Or maybe there is way with string?

Answer 1

If you’re trying to create a string, you need to make sure that the character sequence is terminated with the null character \0.

In other words:

char *c; 
c = new char [m+1];
int i;
    for (i = 0; i < m; i++)
    c[i] = 65 + i;
c[m] = '\0';

Without it, functions on strings like printf won’t know where the string ends.

printf("%s\n",c); // should work now