Question

I need an help to solve an exercise.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct p_prodotto {
    char *costo;
    char *quantita;
};

typedef struct p_prodotto id_prezzo;

struct partecipante {
    id_prezzo *prezzo;
    unsigned short codice;
};

struct partecipante persona[1] = {{{"We", "Ciao"},100}};

int main()
{
    printf ("%s", persona[0].prezzo.costo); // This doesn't works
    return 0;
}

I have the struct p_prodotto with two char pointers inside. There is the typedef, then there is another struct “partecipante” that calls to the type of the struct above.

Is this a case of struct of struct? If so, I need to create an array. I did it like this:

struct partecipante persona[1] = {{{"We", "Ciao"},100}};

Am I doing it wrong? If it is correct, how can I access the “costo” and “quantita” fields?

Thanks in advance for the help.

Answer 1

struct partecipante persona[1] = {{{"We", "Ciao"},100}};

That initialises the struct’s first member as a struct p_prodotto, but it is declared as a pointer to that. Either change struct partecipante to

struct partecipante {
    id_prezzo prezzo;
    unsigned short codice;
};

or initialise it in a different way.

For example

id_prezzo prz = {"We", "Ciao"};
struct partecipante persona[1] = {{&prz,100}};

int main()
{
    printf ("%s", persona[0].prezzo->costo);
    return 0;
}

if you can’t change the definition of struct p_prodotto.