Question

I need an optimised way to replace all trailing characters starting from a ‘/’ in a string.

For example:

mytext = "this is my/string"

i want a result like this

mytext = "this is my/text"

only the string after ‘/’ must be replaced and must be done in optimised way. can anyone find a solution for me?

Answer 1

This seems to be fastest:

s = "this is my/string"
mytext = s[:s.rindex('/')] + '/text'

What I’ve tested:

>>> s = "this is my/string"
>>> pattern = re.compile('/.*$')

>>> %timeit pattern.sub('/text', s)
1000000 loops, best of 3: 730 ns per loop

>>> %timeit s[:s.rindex('/')] + '/text'
1000000 loops, best of 3: 284 ns per loop

>>> %timeit s.rsplit('/', 1)[0] + '/text'
1000000 loops, best of 3: 321 ns per loop