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Home/ Questions/Q 3841820
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T15:42:22+00:00 2026-05-19T15:42:22+00:00

I need get the same type of array that this.form.elements returns, with input names

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I need get the same type of array that this.form.elements returns, with input names as array keys.

I tried this.toArray(), but even though it looks the same, it’s missing the name keys (the keys are numbers).

Here’s the full function:

(function( $ ) {
  $.fn.blah = function(){
    var that = this;
    return this.each(function(){
       $(this).bind('change', function(){
           var matches1 = that.toArray();  // this doesn't work
           var matches2 = this.form.elements;  // this works.

           console.log(matches1); // but both arrays look the same. wtf?
           console.log(matches2);

           return true;
        }).change();

   });
 };

 })(jQuery);

using it as $("input").blah();

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T15:42:22+00:00Added an answer on May 19, 2026 at 3:42 pm

    In javascript you don’t use an Array for named keys. You’d use an Object instead. I assume the values should be the elements themselves.

    var result = {};
    
    $.each(this.form.elements, function() {
        result[ this.name ] = this;
    });
    

    Regarding your update, this line:

    var matches1 = that.toArray();  
    

    …doesn’t work because you’re calling jQuery’s toArray() against a jQuery object.

    If you wanted to use that, you’d call it from the library, and pass it the jQuery object.

    var matches1 = $.toArray( that );  
    

    …although I don’t know why you’d want to turn the jQuery object representing all <input> element into an Array on each change event.

    This line:

    var matches2 = this.form.elements;  // this works.
    

    … works because it is simply a reference to the elements in the form from the <input> element that received the event. It uses native DOM API properties to get a collection (that isn’t technically an Array).


    Had to edit my answer because I was wrong about the use of toArray(). I was thinking of makeArray(). The toArray() method is a wrapper for .get() and does exactly the same thing.

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