Question

I need help figuring out the syntax for the eval function – or even if eval is the right approach. I have a column in my mysql database which holds the name of a PHP function I need to run. There are also PHP variables that would like to leave as variable until they are passed to the function. Below is what I have so far:

eval($valRec[$key]($key,$value));

$valRec is the array which contains the results of a mysql SELECT. $key is a variable which references the name of the column that contains the function name.

$key and $value are the PHP variables that I need to pass into the function.

In the end, I want to end up with:

functionName($key,$value);

which PHP should run.

Hopefully I explained it clearly – thank you in advance for any help!

Answer 1

All you need to do is:

$valRec[$key]($key,$value);

Reference: variable functions.