Question

I need help on regular expression building. There is a line of Javascript:

 navigator.userAgent.match(/Firefox\/3./)

Now it matches only Firefox 3.x. What I need is an expression that will match any Firefox version from 3rd. Meaning Firefox 3, 4, 5, ect.

Any suggestions are welcome!

Answer 1

You can’t do it properly with regex alone. But you can do it with regex + some code:

var m = navigator.userAgent.match(/Firefox\/(\d+)\./);
if (m && m[1] > 3) {
  // .... firefox 3 and above ...
}

note: As for why you can’t do it properly with regex alone, consider Firefox/10.0