Question

I need help rendering data in PHP:

I want to use the results of a SQL query to populate a table, displaying images in a 4-column grid. Here’s what I’ve written so far:

$result = mysql_query("SELECT * FROM gallery ORDER BY id ASC ");

while($row = mysql_fetch_array($result))
{
    echo "<td align=\"center\" ><a href=\"upload_gallery/".$row['image_name']."\" rel=\"prettyPhoto[gallery1]\" title=\" \"><img src=\"upload_gallery/thumbnail/sml_".$row['image_name']."\" width=\"200\" height=\"170\" /></a></td>";
} 

Answer 1

<table><tr>
<?$result = mysql_query("SELECT * FROM gallery ORDER BY id ASC ");
$result =mysql_fetch_array($result)
$count=0;
for($row =0; $row<count($result); $row++)
{
$count++
if($count==4){
echo '</tr><tr>';
$count=0;
}
echo "<td align=\"center\" ><a href=\"upload_gallery/".$row['image_name']."\" rel=\"prettyPhoto[gallery1]\" title=\" \"><img src=\"upload_gallery/thumbnail/sml_".$row['image_name']."\" width=\"200\" height=\"170\" /></a></td>";

} 

?>
</tr>
</table>