I need help thinking up a formula for finding the factors of a number:
Write a method named printFactors that accepts an integer as its
parameter and uses a fencepost loop to print the factors of that
number, separated by the word ” and “. For example, the number 24’s
factors should print as:1 and 2 and 3 and 4 and 6 and 8 and 12 and 24You may assume that the number parameter’s value is greater than 0.
Please don’t give me a COMPLETE program as I would like to try it out myself.
The current code I have has a for loop to control the number of “and’s” appearing, however, I printed out the last number by itself since I don’t want a “24 and” attached to it…
So the output looks something like this at the moment:
“1 and 2 and 3” (I haven’t yet thought up the equation hence the 1,2,3…)
I’m currently thinking that the factors requires a % kind of formula right? Will I need division? I was also thinking of printing out 1 and whatever the number (in this case, 24) you are finding factors for, since 1 and the number itself are always factors of itself.
What else am I missing??
Thanks in advance!! 🙂
Yes.
If you test every number from 1 to n (e.g. from 1 to 24) then 1 and the number itself don’t need to be special cases (because they’ll simply satisfy your ordinary “% kind of formula”).
Maybe 1 is a special case because it doesn’t have the word “and” in front of it.
This may be more complicated than you want, but to find all the factors of n you only need to loop up to the square root of n.