Question

i need in sert data by ajax , i have two pages, once is form that have icon that i click on it and send me to other page and insert new data

here the ajax code

<script type="text/javascript">
$(function() {
  $("#dialog1").click(function() {
        $('#welcome').slideToggle('#loginhandle'); 
        $('#loginhandle').show("slow");

      var name = $("input#ausers_ID").val();
      var dataString = 'ausers_ID='+ ausers_ID  ;
        $.ajax({
               type: "POST",
               url: "OpenCashier.php",
               data: dataString,
               success: function(msg) {
                 $('#loginhandle').slideToggle('#msgreturn');
                 $('#msgreturn').show("slow");
                 $('#msgreturn').html(msg)
                .hide()
                .fadeIn(1500, function() {
        });
      }
     });
    return false;
    });


});
</script>

when i click this bottom

<input type="submit" id="dialog1" name="dialog1" value="Insert" />  

we must call this page

<? session_start();
include("sec.php");
include("../include/connect.php");
include("../include/safe.php");

    if($_POST["dialog1"]){

            // Every thing is OK    
            $ausers_ID=$_POST["ausers_ID"];
            $cashiers_CashierOpenDate=date('Y/m/d');
            $query="INSERT INTO `cashiers` ( `cashiers_CashierID` , `cashiers_CashierOpenDate` , `cashiers_User` , `cashiers_Status` , `cashiers_Delete`  ) VALUES ('', '$cashiers_CashierOpenDate', '$ausers_ID', '0','0');";
            mysql_query($query);
            $num=mysql_affected_rows();         
            if($num==1)
                $message="Account was added successfully";
            else                
                $message=$_POST["dialog1"]." Account is already exists in database";
    }
?>

but data cannot insert why !!!

Answer 1

You missed to include the “dialog1” parameter used in your PHP code.

I would suggest to change your data to sent to :

var dataString = {ausers_ID : ausers_ID, dialog1 : true}