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Home/ Questions/Q 8750059
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T12:48:00+00:00 2026-06-13T12:48:00+00:00

I need my java code to open a file based upon the default application.

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I need my java code to open a file based upon the default application. Thanks to
How to open user system preferred editor for given file? which suggests a quality method to do it by

Runtime.getRuntime().exec("RUNDLL32.EXE SHELL32.DLL,OpenAs_RunDLL "+file);

But the issue is that, once I select the application to open it up, it doesn’t open the file. I do not know the reason for it.

Thanks

EDIT:

Desktop.getDesktop().open(file);

This opens in default application. I want the user to choose the application to open it up

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T12:48:01+00:00Added an answer on June 13, 2026 at 12:48 pm

    Use :

    Desktop.getDesktop().open(file);
    

    http://docs.oracle.com/javase/7/docs/api/java/awt/Desktop.html#open(java.io.File)

    EDIT:

    Here is the code to make your command work:

    import java.io.File;
    import java.io.IOException;
    
    public class TestExec {
    
        public static void main(String[] args) throws IOException, InterruptedException {
            File file = new File("d:/Clipboard1.png");
            ProcessBuilder builder = new ProcessBuilder("RUNDLL32.EXE", "SHELL32.DLL,OpenAs_RunDLL", file.getAbsolutePath());
            builder.redirectErrorStream();
            builder.redirectOutput();
            Process process = builder.start();
            process.waitFor();
        }
    
    }
    
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