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Home/ Questions/Q 6357329
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:08:40+00:00 2026-05-24T23:08:40+00:00

I need simple start an application from my code, like Skype, or other one.

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I need simple start an application from my code, like Skype, or other one.
I read some thread, on the internet, but I haven’t solution.
I tried this methode:

Intent startApp = new Intent("com.android.gesture.builder");
startActivity(startApp);

I wrote this in try/catch blokk, and the LogCat told me: ApplicationNotFound exception handled by Intent. I read the “Hello” tutorial on the Android Developers site, but it’s too comlicated, to my solution…
I can’t register this application starting activity to my manifest file.
I think I need to implement a new class, that extends from Activity, and implement, the code above, and try again?
Please help me, how can I start other application from my main activity easy…

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:08:41+00:00Added an answer on May 24, 2026 at 11:08 pm

    You were nearly there!:

    You just need to supply the package and class of the app you want.

    // Try
    Intent intent = new Intent(Intent.ACTION_VIEW);
    intent.setComponent(new ComponentName("com.htc.Camera", "com.htc.Camera.Camera"));
    startActivity(intent);
    // catch not found (only works on HTC phones)
    

    ComponentName

    I also just saw you can do it a second way:

      PackageManager packageManager = getPackageManager();
      startActivity(packageManager.getLaunchIntentForPackage("com.skype.android"));
    

    See: SOQ Ref

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