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Home/ Questions/Q 8393281
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T19:44:28+00:00 2026-06-09T19:44:28+00:00

I need some help here i have this 2 tables : table clients +——+————-+———–+

  • 0

I need some help here i have this 2 tables :

table "clients"
+------+-------------+-----------+
   id  |  email      |  otherinfo|
+------+-------------+-----------+
   1   |test@ts.ts   |   .....   |
+------+-------------+-----------+
   2   |test2@.ts.ts |   ....    |
+------+-------------+-----------+

table "comptes"
+------+-------------+---------------+
   id  |  login      |   id_clients  | 
+------+-------------+---------------+
 1     |     test    | 1             |
+------+-------------+---------------+
 1     |     test2   | 2             |
+------+-------------+---------------+
 etc.  |    etc.     |       etc..   |
+------+-------------+---------------+

In my website when a user crate an account he give the information of both tables. So i want to test if LOGIN or EMAIL exist in the database before adding them, something like this

'select clients.email,comptes.login    
from clients,comptes     
where clients.email='test2@.ts.ts'
 or comptes.login ='test';

But this query return empty result, i tired other combination but none give the right results .So what i am messing here

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T19:44:30+00:00Added an answer on June 9, 2026 at 7:44 pm

    You don’t need a join at all to see if they exist. The following query returns the id of any matching record:

    select c.id, 'email' as matchtype
    from clients c
    where c.email = <email>
    union all
    select c.id, 'login' as matchtype
    from comptes c
    where c.login = <login>
    

    This gives you the matching ids and tells you where the duplicates are appearing (if that is of interest). If you just want a 0 or 1 flag to specify the existence of duplicates, do this:

    select count(*) as numdups
    from ((select c.id, 'email' as matchtype
           from clients c
           where c.email = <email>
          )
          union all
          (select c.id, 'login' as matchtype
           from comptes c
           where c.login = <login>
         )
        ) t
    
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