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Home/ Questions/Q 6974613
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T17:15:38+00:00 2026-05-27T17:15:38+00:00

I need some help I am trying to create a PHP form using sqlite3

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I need some help I am trying to create a PHP form using sqlite3 database. I am looking up values from from an existing sqlite3 database in the “lookuptable” where the column “id = 340” and display those values as a dropdown selection. Then once the value is selected by the user then the form is submitted by the user which updates the new value in the “roster” table with the values from the php form. I get it to display the names in the dropdown but when I click on the update button to submit the data it updates what the value is in the array.

How do I post “firstname” and “lastname” from the user to the roster table instead of of the number on the array table?

PHP entry page Code:

<html>
<head>
<title></title>
</head>
<div class = "controlbox">
<body style="font-size:12;font-family:verdana">
<form action="post.php" method="post">
<p> 
<h1>  </h1>
<br>
<br>
Person : <select name="name">
<option>--Available Options--</option>
<?php
try
{
$db = new PDO("sqlite:DefaultLibrary.db");
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);   
}
catch(Exception $e)
{   
echo $e->getMessage();
}

$stmt2 = $db->query ("SELECT * FROM lookuptable where ID = '340' ");
$rowarray = $stmt2->fetchall(PDO::FETCH_ASSOC);
$cntr = 0;

foreach($rowarray as $row)
{
 echo "<option value = $cntr >$row[FirstName] $row[LastName]</option>";
 $cntr++;
}
?>

</select><br>

<p>
<input type="submit" name="update" value="update">
</p>

</form>
</body>
</html>

PHP Code: Post.php

<?php

$name = sqlite_escape_string($_POST['name']);

try
{
 $db = new PDO("sqlite:DefaultLibrary.db");
 $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);  
}
catch(Exception $e)
{   
echo $e->getMessage();
}

if (!empty($person)) {
try
{   
    $stmt = $db->prepare("UPDATE roster SET rotationplace = :name WHERE ID = '340'");
    $stmt->bindParam(':name', $name,PDO::PARAM_STR);
    $stmt->execute();
}
catch(Exception $e)
{
    echo $e->getMessage();
}

    echo "submitted successfully";


    }
    ?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:15:39+00:00Added an answer on May 27, 2026 at 5:15 pm

    Try:

    echo "<option value = $INSERT_NAME_HERE_NOT_COUNTER >$row[FirstName] $row[LastName]</option>";
    
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