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Home/ Questions/Q 6654353
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:22:51+00:00 2026-05-26T01:22:51+00:00

I need some help to tweak this regular expression: $content = ‘more <a href=http://www.test.com>test</a>

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I need some help to tweak this regular expression:

$content = 'more <a href="http://www.test.com">test</a> test <a href="mailto:jeff@test.com">Jeff</a> this is a <a href="http://www.test.com">test</a>';

$content = preg_replace("~<a .*?href=[\'|\"]mailto:(.*?)[\'|\"].*?>.*?</a>~", "$1", $content); 

This expression is to strip the html markup off a mailto link and just return the email (jeff@test.com)

It works fine except for in the example I gave above – because a unlimited number of whitespaces is allowed before the href in the pattern, when a website link is before the mailto link, the regex looks all the way forward until it finds the mailto: in the following link and removes all the content in between.

maybe a fix would be to just limit it to two or three whitespaces after the opening tag so as to not look so far ahead, but i wonder if there is a better solution from people who know regex better than I?

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  1. Editorial Team
    Editorial Team
    2026-05-26T01:22:51+00:00Added an answer on May 26, 2026 at 1:22 am

    The problem is not to allow any amount of whitespace, that would be working. The problem is you allow one space and any amount of ANY character with your <a .*

    If you fix this and allow really only whitespace like this

    <a\s+href=[\'|\"]mailto:(.*?)[\'|\"].*?>.*?</a>
    

    it seems to work.

    See it here at Regexr

    But probably you should have a closer look at alex answer (+1 for the example) as this would be the cleaner solution.

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