Question

I need some help with a MySQL query.

I have this table:

Name  | Date       | City
------+------------+------
Peter | 2013-04-01 | Berlin
Paul  | 2013-03-01 | London
Peter | 2013-03-01 | New York 
Peter | 2013-01-28 | Tokio

I need, for each name, the first date and corresponding city in the table.

I tried:

SELECT Name, MIN(Date) as MD, MIN(City) as CN FROM table GROUP BY Name

But the dates don’t corresponds to the city name, the result was:

Peter, 2013-01-028, Berlin

Can anybody give me a hint?

Thanks

Answer 1

You will want to use a subquery to get the min(date) by name and then join that result to your table on both the name and date:

SELECT t1.Name, 
  t1.Date as MD, 
  t1.City as CN 
FROM yourtable t1
inner join
(
  select min(date) MinDate, name
  from yourtable
  group by name
) t2
  on t1.name = t2.name
  and t1.date = t2.mindate

See SQL Fiddle with Demo

The result is:

|  NAME |                             MD |     CN |
---------------------------------------------------
|  Paul |   March, 01 2013 00:00:00+0000 | London |
| Peter | January, 28 2013 00:00:00+0000 |  Tokio |