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Home/ Questions/Q 7566143
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T14:20:11+00:00 2026-05-30T14:20:11+00:00

I need some help with my logic here. I am populating a value from

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I need some help with my logic here. I am populating a value from the database in my select box.

If it exists, I echo the value else i display the default options.

Now, for example if the value from the database is New Jersey, I do not want to display New Jersey for the second time in my drop down box. How do I do that?

    <select name="location" class="field" >

                <option value="<?php if(!empty($get_location)){ echo $get_location; } ?>"><?php if(!empty($get_location)){ echo $get_location; }?></option>

                <option value="New Jersey">New Jersey</option>

                <option value="New York">New York</option>

                <option value="California">California</option>
            </select>
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  1. Editorial Team
    Editorial Team
    2026-05-30T14:20:12+00:00Added an answer on May 30, 2026 at 2:20 pm

    You make an if statement in every option field and check if the value from the database matches the value of the option field and if it does so you echo "selected=\"true\"" to the option field.

    For a code example see my answer for this question:
    retieve data from mysql and display in form

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