Question

I need the regex expression to remove any text before a match and including the match

eg. I want to remove “123S” and everything before it, I know I can do this with

    string.replaceAll("^.*?(?=[123S])","");
    string.replaceAll("123S","");

But really want to do it in a single expression (can’t find another example anywhere!)

Answer 1

You can do it with:

string.replaceAll("^.*123S","");

Remove non-greedy ? to match last occurence and .* everything before.