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Home/ Questions/Q 8026765
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T23:35:47+00:00 2026-06-04T23:35:47+00:00

I need this for charting purposes. Basically i have to: Select all sent SMS

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I need this for charting purposes. Basically i have to:

  1. Select all sent SMS by date without time part, getting an array with dates/counts pairs day-by-day;
  2. Add “fake” rows for days without any record in my table, that is filling all dates “gaps” with zeroes.

An example result and corresponding table (here simplified) would be:

array(
    '2012-05-26 00:00:00' => 1,
    '2012-05-27 00:00:00' => 0, // Fake added row
    '2012-05-28 00:00:00' => 2,
)

+----------------+----------------------+
| Table SMS | id | sent_at              |
+----------------+----------------------+
|           |  1 | 2012-05-26 21:58:41  |
+----------------+----------------------+
|           |  2 | 2012-05-28 22:19:21  |
+----------------+----------------------+
|           |  3 | 2012-05-28 02:19:21  |
+----------------+----------------------+

Is there any SQL command for doing this or should i do manually playing with PHP arrays?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T23:35:49+00:00Added an answer on June 4, 2026 at 11:35 pm

    You can use a UNION Statement

    SELECT 
       sent_at,
       Count(*)
    FROM (Select
            id,
            DATE(sent_at) as sent_at
          FROM TableName 
          Group by Date(sent_at)
          UNION ALL
          Select
            '0' as id,
            DATE('2012-05-27') as sent_at) derived_table
    Group By sent_at
    

    Edited

    I suggested creating a special table to join against.

    Creation of a datetable for querying

    CREATE TABLE DateTable (
      DateValue DateTime,
      Year Int,
      Month Int,
      Day Int)
    

    Now populate this table with all date values within the ranges you are querying. You can easily join to this table with any valid date. Allowing you to aggregate for Dates that do and do not exist.

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