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Home/ Questions/Q 9172323
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T16:19:06+00:00 2026-06-17T16:19:06+00:00

I need to add new namespaces to the rss(root) element of my feed, in

  • 0

I need to add new namespaces to the rss(root) element of my feed, in addition to a10:

<rss xmlns:a10="http://www.w3.org/2005/Atom" version="2.0">
    <channel>
.
.
.

I am using a SyndicationFeed class serialized to RSS 2.0 and I use a XmlWriter to output the feed,

var feed = new SyndicationFeed(
                    feedDefinition.Title,
                    feedDefinition.Description,
     .
     .
     .



using (var writer = XmlWriter.Create(context.HttpContext.Response.Output, settings))
        {
            rssFormatter.WriteTo(writer);
        }

I have tried adding AttributeExtensions on SyndicationFeed but it adds the new namespaces
to the channel element instead of the root,

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T16:19:07+00:00Added an answer on June 17, 2026 at 4:19 pm

    Unfortunately the formatter is not extensible in the way you need.

    You can use an intermediate XmlDocument and modify it before writing to the final output.

    This code will add a namespace to the root element of the final xml output:

    var feed = new SyndicationFeed("foo", "bar", new Uri("http://www.example.com"));
    var rssFeedFormatter = new Rss20FeedFormatter(feed);
    
    // Create a new  XmlDocument in order to modify the root element
    var xmlDoc = new XmlDocument();
    
    // Write the RSS formatted feed directly into the xml doc
    using(var xw = xmlDoc.CreateNavigator().AppendChild() )
    {
        rssFeedFormatter.WriteTo(xw);
    }
    
    // modify the document as you want
    xmlDoc.DocumentElement.SetAttribute("xmlns:example", "www.example.com");
    
    // now create your writer and output to it:
    var sb = new StringBuilder();
    using (XmlWriter writer = XmlWriter.Create(sb))
    {
        xmlDoc.WriteTo(writer);
    }
    
    Console.WriteLine(sb.ToString());
    
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