Question

I need to add the numbers in the row array mentioned in the structure.
for example I need the output of row=[ 4 5 6]
and age= 25, how can i do with the above mentioned structure??
Please help !

#include<stdio.h>

typedef struct person
{
    int row[1];
    int age;
} PERSON;

int main()
{
    PERSON p;
    PERSON *pptr=&p;

    pptr->row[1] = 4;
    pptr->age = 25;
    printf("%d\n",pptr->row[1]);
    printf("%d\n",pptr->age);
    return 0;
}

Answer 1

I need to add the numbers in the row array mentioned in the structure. for example I need the output of row=[ 4 5 6] and age= 25, how can i do with the above mentioned structure?? Please help !

Based on this update:

Put the number of elements you want to store into the array defination:

int row[1]; // This stores 1 element of type int

// you want to store 3 elements: 4, 5, 6, so...

int row[3];  // This is what you're looking for

Remember an array:

int row[X];

Goes from row[0] to row[X-1]. So in your case X=3 that means your min/max values for your array are:

min = row[0]
max = row[3-1] = row[2]

That means your code should do something like:

pptr->row[0] = 4;
pptr->row[1] = 5;
pptr->row[2] = 6;
pptr->age = 25;
printf("%d\n",pptr->row[0]);
printf("%d\n",pptr->row[1]);
printf("%d\n",pptr->row[2]);
printf("%d\n",pptr->age);