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Home/ Questions/Q 5849885
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T13:03:48+00:00 2026-05-22T13:03:48+00:00

I need to alloc a large multidimensional-array as char a[x][32][y] , and x*32*y is

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I need to alloc a large multidimensional-array as char a[x][32][y], and x*32*y is about 6~12G. (x, y are detenmined at runtime.)

I think out a way that is to do char *a=malloc(x*32*y), and use *(a+32*y*i+y*j+k) for a[i][j][k].

However, this looks not so convient comparing to a[i][j][k].

Is there any better way ?

Added:
It is a[x][32][datlen], where datlen is detenmined at runtime and x is set considering the memory.

The whole data in the array will be new. And I have got mathines with 16 or 32GB memory to run it.

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  1. Editorial Team
    Editorial Team
    2026-05-22T13:03:49+00:00Added an answer on May 22, 2026 at 1:03 pm

    INCORRECT: You should still be able to use a[i][j][k] syntax when referencing dynamically allocated memory.

    CORRECT: Use a macro to at least make the job easier

    #define A(i,j,k) *(a+32*y*i+y*j+k)
    A(1,2,3) would then do the right thing.
    
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