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Home/ Questions/Q 3787240
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T11:48:36+00:00 2026-05-19T11:48:36+00:00

I need to be able to have an n-dimensional field where n is based

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I need to be able to have an n-dimensional field where n is based on an input to the constructor. But I’m not even sure if that’s possible. Is it?

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  1. Editorial Team
    Editorial Team
    2026-05-19T11:48:36+00:00Added an answer on May 19, 2026 at 11:48 am

    Quick solution: you could approximate it with a non-generic ArrayList of ArrayList of … going as deep as you need to. However, this may get awkward to use pretty fast.

    An alternative requiring more work could be to implement your own type using an underlying flat array representation where you calculate the indexing internally, and providing accessor methods with vararg parameters. I am not sure if it is fully workable, but may be worth a try…

    Rough example (not tested, no overflow checking, error handling etc. but hopefully communicates the basic idea):

    class NDimensionalArray {
      private Object[] array; // internal representation of the N-dimensional array
      private int[] dimensions; // dimensions of the array
      private int[] multipliers; // used to calculate the index in the internal array
    
      NDimensionalArray(int... dimensions) {
        int arraySize = 1;
    
        multipliers = new int[dimensions.length];
        for (int idx = dimensions.length - 1; idx >= 0; idx--) {
          multipliers[idx] = arraySize;
          arraySize *= dimensions[idx];
        }
        array = new Object[arraySize];
        this.dimensions = dimensions;
      }
      ...
      public Object get(int... indices) {
        assert indices.length == dimensions.length;
        int internalIndex = 0;
    
        for (int idx = 0; idx < indices.length; idx++) {
          internalIndex += indices[idx] * multipliers[idx];
        }
        return array[internalIndex];
      }
      ...
    }
    
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