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Home/ Questions/Q 549357
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:10:33+00:00 2026-05-13T11:10:33+00:00

I need to be able to rotate an image around a given point so

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I need to be able to rotate an image around a given point so that what ever part of the image appears in the center of my container is the center of rotation.

To calculate the center points, I am currently just taking the inverse of the translation applied to the image:

Rotate.CenterX = Translate.X * -1;
Rotate.CenterY = Translate.Y * -1;

However, the current calculation i’m using is not sufficient as it does not work if the image has been translated after being rotated.

I’m sure it’s a reasonably straight forward trig function, I just can’t think what it is!

Cheers

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:10:34+00:00Added an answer on May 13, 2026 at 11:10 am

    If you are working with GDI+ then use the following:

    double ImWidth = (double)Im.Width;
    double ImHeight = (double)Im.Height;
    double XTrans = -(ImWidth * X);
    double YTrans = -(ImHeight * Y);
    
    g.TranslateTransform((float)XTrans, (float)YTrans);    
    g.TranslateTransform((float)(ImWidth / 2.0 - XTrans), (float)(ImHeight / 2.0 - YTrans));
    g.RotateTransform((float)Angle);
    g.TranslateTransform(-((float)(ImWidth / 2.0 - XTrans)), -((float)(ImHeight / 2.0 - YTrans)));
    

    If you are working with WPF graphic objects, use the following transform group:

    TransformGroup TC = new TransformGroup();
    RotateTransform RT = new RotateTransform(Angle);
    RT.CenterX = Im.Width / 2.0;
    RT.CenterY = Im.Height / 2.0;
    TranslateTransform TT = new TranslateTransform(-X * Im.PixelWidth, -Y * Im.PixelHeight);
    TC.Children.Add(TT);
    TC.Children.Add(RT);
    

    X & Y are the percent values you want to translate the image in (if the image is 1000 pixels and X is 0.1 then the image will be translated 100 pixels). This is how I needed the function to work but you can easily change it otherwise.

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