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Home/ Questions/Q 6885081
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T05:35:25+00:00 2026-05-27T05:35:25+00:00

I need to bring some data into an IObservable stream. I want to use

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I need to bring some data into an IObservable stream. I want to use an extension method on IObservable to do this, but i am not sure how to do it.

The data is produced by a simple class that has this signature:

interface Process<TIn, TOut> {
    void Do(TIn data);
    event Action<TOut> Result;
}

i.e. to start the process I have to call Do(...) and the result is sent to the event Result(...). This can’t be changed!

I want to bring this data into an Rx process, that handles user input in this way:

subject.AsObservable<string>   // this produces the observable of user inputs
       .Throttle(TimeSpan.FromMilliseconds(typingDelay))
       .DistinctUntilChanged()

       .Process(myProcess)     // this is what I need help for

       .Switch()
       .Subscribe(myConsumer)

This is from adopted from the standard example of delayed user input triggering a web service (or something else that is long-running and has to be async) in the Hands-on Labs.

Whenever the user continues to enter, all observables that are still “underway” must be cancelled (therefore the Switch()). So my Process() has to return an IObservable<IObservable<TOut>> to make the switch work correctly.

I’m really stuck here. Does anyone has a hint for me how to write this Process(...) extension method?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T05:35:25+00:00Added an answer on May 27, 2026 at 5:35 am

    I’ve modified your Process interface to use generics properly and provided a dummy implementation of the interface like so:

    interface IProcess<T, R>
    {
        void Do(T data);
        event Action<IEnumerable<R>> Result;
    }
    
    public class ProcessImpl<T, R> : IProcess<T, R>
    {
        public void Do(T data) { }
        public event Action<IEnumerable<R>> Result;
    }
    

    Now you can write the extension method like this:

    public static IObservable<IObservable<R>> Process<T, R>(this T @this)
    {
        return Observable.Create<IObservable<R>>(o =>
        {
            var p = new ProcessImpl<T, R>();
            var subscription =
                Observable
                    .FromEvent<IEnumerable<R>>(
                        h => p.Result += h,
                        h => p.Result -= h)
                    .Take(1)
                    .Select(x => x.ToObservable())
                    .Subscribe(o);
            p.Do(@this);
            return subscription;
        });
    }
    

    Does this work for you?

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