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Home/ Questions/Q 8811567
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T03:23:49+00:00 2026-06-14T03:23:49+00:00

I need to build a hash based on FirstName/LastName combo. In the database both

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I need to build a hash based on FirstName/LastName combo. In the database both are 100 chars each max and the hash needs to be 20 chars max.

Is there a way to reliably generate a unique value based on that? Assume that FirstName/LastName combo is unique.

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  1. Editorial Team
    Editorial Team
    2026-06-14T03:23:51+00:00Added an answer on June 14, 2026 at 3:23 am

    It sounds like you want a unique identifier for each record in the table and that this identifier is not easy to guess. There are multiple ways to achieve this, including:

    1. Add a column for the identifier with a unique constraint and generate a random identifier when you insert the column. If the insertion fails due the identifier already being present, generate a new identifier and try again.

    2. Add a auto GUID column to the table to let the database generate a unique identifier.

    3. Add a auto-increment int column to the table to let the database generate a unique identifier and obfuscate that. You can do this, for example, by padding the integer to 16 and encrypting it with a 128-bit block cipher. Example:

    private static readonly AesManaged cipher = new AesManaged()
    {
        BlockSize = 128,
        Key = Encoding.UTF8.GetBytes("secret__secret__"),
        Mode = CipherMode.ECB,
        Padding = PaddingMode.None
    };
    
    static string Obfuscate(int id)
    {
        using (var transform = cipher.CreateEncryptor())
        {
            return Convert.ToBase64String(
                transform.TransformFinalBlock(
                    Encoding.UTF8.GetBytes(
                        id.ToString("0000000000000000")), 0, 16));
        }
    }
    
    static int Deobfuscate(string s)
    {
        using (var transform = cipher.CreateDecryptor())
        {
            return int.Parse(
                Encoding.UTF8.GetString(
                    transform.TransformFinalBlock(
                        Convert.FromBase64String(s), 0, 16)));
        }
    }
    

    Note that none of these ways make it impossible to guess the identifier, just more difficult than incrementing an integer by 1. You still need to check if the user is authorised to view the information associated with the identifier.

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