Question

I need to calculate the year diferences between two dates.

Tried using DATEDIFF but that only do the less of the dates, for example:

Date 1: 07/03/2011
Date 2: 07/02/2012

(Date format MM/DD/YYYY)

Then: DATEDIFF([yyyy], ’07/03/2011′, ’07/02/2012′) = 1

But the real diferences are 0 year.

Answer 1

Since noone had a correct solution i post mine even though noone will ever notice.

declare @d1 datetime
declare @d2 datetime

set @d1 = '1968-02-29'
set @d2 = '2011-02-28'

select datediff(year, @d1, @d2)-
case when month(@d1)*32 + day(@d1) > month(@d2) * 32 + day(@d2) then 1 else 0 end
--case when month(@d2)*32 + day(@d1) > month(@d2) * 32 + day(@d2) then 1 else 0 end

This method is basically the same as the next method, difference is that it is done with numbers to avoid the casting, which i was told was slower.

select datediff(year, @d1, @d2)- 
case when convert(char(5),@d1, 1) > convert(char(5),@d2, 1) then 1 else 0 end