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Home/ Questions/Q 8671301
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T18:55:01+00:00 2026-06-12T18:55:01+00:00

I need to call a method that accepts an interface as a parameter. The

  • 0

I need to call a method that accepts an interface as a parameter. The object I am using as a parameter implements the inteface however I still get a compile error. What am I doing wrong?

public class ViewModel 
{
    public ViewModel()
    {
        QueueManager<CFMessage<CFQueueItem>, CFQueueItem> q = new QueueManager<CFMessage<CFQueueItem>, CFQueueItem>();
        DoSomething(q);     // This line does not compile:  Cannot convert from QueueManager<CFQueueItem> to QueueManager<IQueueItem>
    }

    public void DoSomething(QueueManager<IQueueMessage<IQueueItem>, IQueueItem> queueManager)
    {

    }
}

public interface IQueueMessage<T> where T : IQueueItem
{
    int ID { get; set; }
}

public interface IQueueItem
{
    int ID { get; set; }
}

public class CFMessage<CFQueueItem> : IQueueMessage<CFQueueItem> where CFQueueItem : IQueueItem
{
    public int ID { get; set; }
}

public class CFQueueItem : IQueueItem
{
    public int ID { get; set; }
}

public class QueueManager<T, Q>
    where T : IQueueMessage<Q>
    where Q : IQueueItem
{

}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T18:55:03+00:00Added an answer on June 12, 2026 at 6:55 pm

    You can work around by using concept covariance, define interface IQueueMessage as covariant, using keyword out:

    public interface IQueueMessage<out T> where T : IQueueItem
    {
    }
    

    Then create new covariant interface IQueueManager for QueueManager:

    public interface IQueueManager<out T, out Q> where T : IQueueMessage<Q>
                                                 where Q : IQueueItem
    {
    }
    
    public class QueueManager<T, Q> : IQueueManager<T, Q>
        where T : IQueueMessage<Q>
        where Q : IQueueItem
    {
    
    }
    

    Then you can use this interface for method DoSomething:

    public void DoSomething(IQueueManager<IQueueMessage<IQueueItem>, IQueueItem> queueManager)
    {
    }
    

    Your code will compile successfully:

    public ViewModel()
    {
        var q = new QueueManager<CFMessage<CFQueueItem>, CFQueueItem>();
        DoSomething(q);
    }
    
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