I need to change existing xml in order to make an excel table from it.
My xml that needs to be changed:
<rows>
<row>
<cell image="blank.gif">Row1</cell>
<cell>1</cell>
<cell>2</cell>
<cell>3</cell>
<cell>4</cell>
<cell>5</cell>
<cell>6</cell>
<cell>7</cell>
<row>
<cell image="blank.gif">Row1_1</cell>
<cell>8</cell>
<cell>9</cell>
<cell>10</cell>
<cell>11</cell>
<cell>12</cell>
<cell>13</cell>
<cell>14</cell>
</row>
<row>
<cell image="blank.gif">Row1_2</cell>
<cell>15</cell>
<cell>16</cell>
<cell>17</cell>
<cell>18</cell>
<cell>19</cell>
<cell>20</cell>
<cell>21</cell>
</row>
</row>
<row>
<cell image="blank.gif">Row2</cell>
<cell>22</cell>
<cell>23</cell>
<cell>24</cell>
<cell>25</cell>
<cell>26</cell>
<cell>27</cell>
<cell>28</cell>
</row>
</rows>
My current XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="rows">
<xsl:element name="sheetData">
<xsl:apply-templates select="row"></xsl:apply-templates>
</xsl:element>
</xsl:template>
<xsl:template match="row">
<xsl:variable name="rowID">
<xsl:number value="position()" format="1"/>
</xsl:variable>
<xsl:element name="row">
<xsl:attribute name="r">
<xsl:value-of select="$rowID"/>
</xsl:attribute>
<xsl:for-each select="*">
<xsl:element name="c">
<xsl:variable name="colID">
<xsl:number value="position()" format="A"/>
</xsl:variable>
<xsl:attribute name="r">
<xsl:value-of select="concat(string($colID),string($rowID))"/>
</xsl:attribute>
<xsl:attribute name="t">
<xsl:text>inlineStr</xsl:text>
</xsl:attribute>
<xsl:element name="is">
<xsl:element name="t">
<xsl:value-of select="."/>
</xsl:element>
</xsl:element>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
My output from the transformations:
<sheetData>
<row r="1">
<c r="A1" t="inlineStr">
<is>
<t>Row1</t>
</is>
</c>
<c r="B1" t="inlineStr">
<is>
<t>1</t>
</is>
</c>
<c r="C1" t="inlineStr">
<is>
<t>2</t>
</is>
</c>
<c r="D1" t="inlineStr">
<is>
<t>3</t>
</is>
</c>
<c r="E1" t="inlineStr">
<is>
<t>4</t>
</is>
</c>
<c r="F1" t="inlineStr">
<is>
<t>5</t>
</is>
</c>
<c r="G1" t="inlineStr">
<is>
<t>6</t>
</is>
</c>
<c r="H1" t="inlineStr">
<is>
<t>7</t>
</is>
</c>
<c r="I1" t="inlineStr">
<is>
<t>Row1_1891011121314</t>
</is>
</c>
<c r="J1" t="inlineStr">
<is>
<t>Row1_215161718192021</t>
</is>
</c>
</row>
<row r="2">
<c r="A2" t="inlineStr">
<is>
<t>Row2</t>
</is>
</c>
<c r="B2" t="inlineStr">
<is>
<t>22</t>
</is>
</c>
<c r="C2" t="inlineStr">
<is>
<t>23</t>
</is>
</c>
<c r="D2" t="inlineStr">
<is>
<t>24</t>
</is>
</c>
<c r="E2" t="inlineStr">
<is>
<t>25</t>
</is>
</c>
<c r="F2" t="inlineStr">
<is>
<t>26</t>
</is>
</c>
<c r="G2" t="inlineStr">
<is>
<t>27</t>
</is>
</c>
<c r="H2" t="inlineStr">
<is>
<t>28</t>
</is>
</c>
</row>
</sheetData>
And a screenshot from the generated excel document:
So my problem is the nested rows i need to show them exactly like Row1 and Row2
I think what you are saying is that you want a separate row in the output for each row in the input XML, even though the row elements are nested.
To start with then, you need to replace this line
With this…
This will ensure only the cell elements are output in the current row, and the nested row elements won’t be processed.
Then, after you have created the row element with just the cell elements, you can look for the nested row elements to output these
Do note there is no real need to use xsl:element to output static named elements, just write out the element directly. Your code can also be tidied up by making use of Attribute Value Templates to create attributes, rather than using xsl:attribute
Try the following XSLT:
When applied to your XML, the following is output