Question

I need to contruct a query, from keywords entered by a user in a text-field, which will do the following: Take the keywords and search in a table, after which car has all the given keywords, less than all and continuing down the car which has just one keyword.
My table looks like this:

field_id | car_id | keyword |
----------------------------
1        | 5       | 1989   |
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2        | 8       | old    |
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3        | 8       | ford   |
-----------------------------
6        | 8       | cheap  |
-----------------------------
4        | 7       | ford   |
-----------------------------
6        | 7       | cheap  |
-----------------------------
5        | 6       | ford   |
-----------------------------

Say if the user searched for “old”, “ford” and “cheap”, car_id 8, 7 and 6 should be returned because they contains the keywords. Furthermore I need to know which car has which keywords (8: “old”, “ford”, “cheap” And 7: “ford”, “cheap” And 6: “ford”) . Im not an expert with MySQL so I don’t now if it is possible to create some sort of multidimensional array here…

I have a query which select only the car which has all the keywords entered, if it is of any use:

Select car_id from keywords 
Where keyword in ("old","ford", "cheap") 
group by car_id having count(*) = 3;    

Answer 1

You dont need having because it will only send whenever there exist only 3 cars belongs to given keywords. Try this

Select car_id from keywords ,,GROUP_CONCAT(keyword)
Where keyword in ("old","ford", "cheap") 
group by car_id 

This will give you comma separated keywords that belongs to car